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Q.

For the cell Zn(s)Zn2+Cu2+Cu(s), the standard cell voltage, Ecell 0 is 1.10V. When a cell using these reagents was prepared in the lab, the measured cell voltage was 0.98 V. One possible explanation for the observed voltage is

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a

the [Zn2+] was larger than the [Cu2+]

b

there was 2.00 mol of Cu2+ but only 1.00 mol of Zn2+

c

the Zn electrode had twice the surface of the Cu electrode

d

the volume of the Zn2+ solution was larger than the volume of the Cu2+ solution

answer is C.

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Detailed Solution

Zn+Cu+2Cu+Zn+2E=E0+(0.0591/2)logCu+2/Zn+2=0.98E0=1.1;So,Zn+2>Cu+2

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