Q.

For the cell Zn/Zn2+//Cu2+/Cu if the concentration of Zn2+ and Cu2+ ions is doubled, the emf of the cell

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a

remains same

b

reduces to half

c

 remains zero

d

doubles

answer is C.

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Detailed Solution

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For the galvanic cell , the Nernst equation is written as 

Ecell=Ecello-0.0591n log [Zn2+][Cu2+]

Hence Ecell remains same, when conc. of both [Zn2+]  and  [Cu 2+] is doubled.

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