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Q.

For the chemical reaction at temperature 298 K, A(g)⇌B(g)  ΔGo=−413.15 cal / mole
 Concentration (mole/litre) vs. time graph is given below. Identify the correct graph for the above reaction.
 

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a

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b

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c

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d

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answer is C.

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Detailed Solution

ΔG∘=−2.303RTlog10Keq.−413.15=−2.303×2×298log10Keq.=0.3010=log10KeqKeq=2Hence, graph (C) matches correctly

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