For the circuit shown in figure

a) $R_{net}=2+1.2=3.2k\Omega$

$i=\frac{V}{R_{net}}=\frac{24}{3.2}mA=7.5mA$

b) The potential difference across $R_L$ is $\frac{1.2}{1.2+2}\times 24=9V$

c) Power dissipated in $R_1$ is $\frac{{\left(15\right)}^2}{2\times {10}^3}=\frac{225}{2}mW$

Power dissipated in $R_2$ is $\frac{{\left(9\right)}^2}{6\times {10}^3}=\frac{27}{2}mW$

Ratio of powers dissipated in $R_1$ and $R_2$ is $\frac{225}{27}=\frac{25}{3}$

d) Before interchanging, power dissipated in $R_L$ is $\frac{{\left(9\right)}^2}{1.5}mW$

After interchanging, power dissipated in $R_L$ is $\frac{{\left(3\right)}^2}{1.5}mW$

The magnitude of the power dissipated in $R_L$ decreased by a factor of 9.