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For the coagulation of 50 ml of ferric hydroxide sol 10 ml 0.5 M $K C l$ is required. What is the coagulation value of $K C l$ ?

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100

answer is C.

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Detailed Solution

Coagulation value $= \frac{n o o f m i l \lim o l e s o f e l e c t r o l y t e r e q u i r e d}{v o l u m e o f c o l l o i d a l s o l u t i o n i n l i t o e s}$

$= \frac{10 \times .5 \times 1000}{50} = 100$

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