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Q.

For the coagulation of a negative sol, the species below, that has the highest flocculating power is

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a

${SO}_{4}^{2 -}$

b

${Ba}^{2 +}$

c

${Na}^{+}$

d

${PO}_{4}^{3}$

answer is B.

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Detailed Solution

For a negative sol, a positive ion is required for flocculation.
Greater the valence of the flocculating ion added, the greater is its power to cause precipitation.
This is called Hardy-Schulz law.
So, Ba⁺² has the highest flocculating power.

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