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Q.

For the decolorisation of one mole of KMnO₄ in acidic medium the number of moles of H₂O₂ required is

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a

5/2

b

7/2

c

3/2

d

1/2

answer is C.

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Detailed Solution

$\mathop {2KMn{O_4}}\limits^{ + 7} + 5{H_2}{O_2} + 3{H_2}S{O_4}\xrightarrow{{}}{K_2}S{O_4} + 2\mathop {Mn}\limits^{ + 2} S{O_4} + 8{H_2}O + 5{O_2}\$

From balanced equation:

KMnO₄ H₂O₂

2 moles → 5 moles

1 mole → ? moles

$\large \frac{1 \times 5}{2} = 2.5 moles$

⇒ i.e., 2 moles of KMnO₄ decolonised (or) reduced by 5-moles of H₂O₂

where as 1 mole of KMnO₄ is decolonised by ___moles of H₂O₂

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