Q.

For the decomposition of the compound represented as NH2COONH4( s)2NH3( g)+CO2( g) the Kp=2.9×10-5 atm3. If the reaction is started with 1 mol of the compound, the total pressure at equilibrium would be

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a

5.82×10-2 atm

b

38.8×10-2 atm

c

7.66×10-2 atm

d

1.94×10-2 atm

answer is B.

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Detailed Solution

NH2COONH4(s)2NH3(g)+CO2(g)Kp=pNH32pCO2=(2p)2(p)=4p3p=Kp41/3=2.9×105atm341/3=0.01935atmptotal =pNH3+pCO2=2p+p=3p=3×0.01935atm=5.81×102atm

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