For the decomposition of $N_{2} O_{5} (g)$ it is given that
$\begin{aligned} 2 N_{2} O_{5} (g) \to 4 {NO}_{2} (g) + O_{2} (g) \\ N_{2} O_{5} (g) \to 2 {NO}_{2} (g) + \frac{1}{2} O_{2} (g) \end{aligned}$ activation energy $E_{a}$
activation energy $E_{a}^{'}$ then

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$E_{a} = E_{a}^{'}$

$E_{a} > E_{a}^{'}$

$E_{a} < E_{a}^{'}$

$E_{a} = 2 E_{a}^{'}$

answer is A.

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Detailed Solution

The stoichiometry of change has no bearing on the energy of activation. It represents a certain value for a given change.

Thus in this case, $E_{a} = E_{a}^{'}$

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