For the dissociation: ${\text{N}}_{\text{2}}{\text{O}}_{\text{5}\left(\text{g}\right)}\rightleftharpoons {\text{\hspace{0.17em}2NO}}_{\text{2}\left(\text{g}\right)}\text{\hspace{0.17em}+\hspace{0.17em}}\frac{\text{1}}{\text{2}}{\text{\hspace{0.17em}O}}_{\text{2}\left(\text{g}\right)}$. If, M = Molecular mass of ${\text{N}}_{\text{2}}{\text{O}}_{\text{5}\left(\text{g}\right)}$ ; D =

vapour density of equilibrium mixture; P° = Initial pressure of ${\text{N}}_{\text{2}}{\text{O}}_{\text{5}\left(\text{g}\right)}$. Identify the ‘true’ statements :

Equilibrium pressure can be expressed as $\frac{\text{2P°D}}{\text{M}}$

Increase in temperature will lower the magnitude of D

Equilibrium pressure can be expressed as $\frac{\text{P°M}}{\text{2D}}$

Degree of dissociation can be expressed as $\frac{\text{P°}(\text{M\hspace{0.17em}}-\text{\hspace{0.17em}2D})}{\text{3D}}$