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Q.

For the dissolution of 1 mole of NaCl at 298 K in water the following data is obtained.

Lattice energy = 777.92 kJ/mole,hydration energy = -774 kJ/mole and ∆S=0.04kJ/K/Mole.∆G for dissoution of 1 mole of NaCl at same temperature is

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a

-8J/mole

b

-8kJ/mole

c

+8kJ/mole

d

+8J/mole

answer is A.

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Detailed Solution

when NaCl is dissolved in water lattice energy is absorbed and hydration energy is given out.

∆G=∆H-T∆S=L.E+H.E-T∆S

= 777.92 - 774 - 298(0.04) = -8 kJ/mole

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