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For the electrochemical cell, ${Ag}^{-} | AgCl | KCl ∥ {AgNO}_{3} ∣ {Ag}^{+}$ the overall cell reaction is

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${Ag}^{+} + {Cl}^{-} ⟶ AgCl (s)$

${Ag}^{+} + KCl ⟶ AgCl (s) + K^{+}$

$Ag + AgCl ⟶ 2 Ag +^{} \frac{1}{2} {Cl}_{2}$

$AgCl (s) ⟶ {Ag}^{+} + Cl$

answer is C.

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Detailed Solution

$C a t h o d e : A g C l_{(s)} + e^{-} \to A g + C l_{(a q)}^{-} A n o d e : A g \to A g_{(a q)}^{+} + e^{-} T h e o v e r a l l r e a c t i o n i s A g C l_{(s)} \to A g_{(a q)}^{+} + C l_{(a q)}^{-}$

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