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Q.

For the electrolyte of type A₂B,Ksp is given then its solubility is calculated by

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a

$\sqrt[3]{\frac{ksp}{4}}$

b

$\sqrt{ksp / 4}$

c

$\frac{ksp}{4}$

d

$\sqrt[3]{ksp}$

answer is B.

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Detailed Solution

$For A_{2} B ksp = 4 s^{3} s = \sqrt[3]{\frac{ksp}{4}}$

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For the electrolyte of type A2B,Ksp is given then its solubility is calculated by