For the electrolytic production of ${\mathrm{NaClO}}_4$ from ${\mathrm{NaClO}}_3$ according to the equation ${\mathrm{NaClO}}_3 + {\mathrm{H}}_2\mathrm{O} \to {\mathrm{NaClO}}_4 + {\mathrm{H}}_2$, the number of Faradays of electricity required to produce 0.5 mole of ${\mathrm{NaClO}}_4$ is