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For the equation $x^{3} + 3 x^{2} - x - 2 = 0$ if $s_{1}, s_{2}, s_{3}$ have their usual notation then

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$s_{2} < s_{1} < s_{3}$

$s_{3} < s_{1} < s_{2}$

$s_{1} < s_{2} < s_{3}$

$s_{1} < s_{3} < s_{2}$

answer is B.

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Detailed Solution

$\begin{array}{l} G i v e n E q u a t i o n x^{3} + 3 x^{2} - x - 2 = 0 \\ s_{1} = \frac{- 3}{1} = - 3 \\ s_{2} = \frac{- 1}{1} = - 1 \\ s_{3} = \frac{- (- 2)}{1} = 2 \\ ∴ s_{1} < s_{2} < s_{3} \end{array}$

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