For the equilibrium Kp = 0.82 atm at 270C. At the same temperature its Kc in mol lit-1 is (R = 0.082 lit atm mol-1 K-1)

Δng = nP (g) -nR (g)Δng = 2 - 1Δng = 1KP = KC (RT)Δn0.82 = KC (0.0821 ×300)1

For the equilibrium Kp = 0.82 atm at 270C. At the same temperature its Kc in mol lit-1 is (R = 0.082 lit atm mol-1 K-1)

Δng = nP (g) -nR (g)Δng = 2 - 1Δng = 1KP = KC (RT)Δn0.82 = KC (0.0821 ×300)1

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For the equilibrium $large {A_{(g)}}, rightleftharpoons ,{B_{(g)}}, + ,{C_{(g)}};$ K_p = 0.82 atm at 27⁰C. At the same temperature its K_c in mol lit^-1 is (R = 0.082 lit atm mol^-1 K^-1)

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large {A_{(g)}}, rightleftharpoons ,{B_{(g)}}, + ,{C_{(g)}};

Δn_g = n_P (g) -n_R (g)

Δn_g = 2 - 1

Δn_g = 1

K_P = K_C (RT)^Δn
0.82 = K_C (0.0821 $\times$ 300)¹

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For the equilibrium Kp = 0.82 atm at 270C. At the same temperature its Kc in mol lit-1 is (R = 0.082 lit atm mol-1 K-1)

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For the equilibrium $large {A_{(g)}}, rightleftharpoons ,{B_{(g)}}, + ,{C_{(g)}};$ K_p = 0.82 atm at 27⁰C. At the same temperature its K_c in mol lit^-1 is (R = 0.082 lit atm mol^-1 K^-1)