Q.

For the equilibrium
CuSO45H2O(s)CuSO43H2O(s)+2H2O(g) Kp=2.25×104atm2 and vapour pressure of water is 22.8 Torr at 298 K.CuSO45H2O(s) is efflorescent (i.e., loses water) 

when relative humidity is :

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a

less than 33.3 %

b

less than 50 %

c

less than 66.6%

d

above 66.6%

answer is B.

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Detailed Solution

Here, the pressure on the water molecule,

PH2O2=2.25×104PH2O=1.5×102atm

Relative humanity=1.5×10222.8×760=0.5 or 50%

If Relative humanity >50% Rxn goes backward.

If Relative humanity <50% CuSO45H2O(s) becomes efflorescent.

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