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Q.

For the estimation of nitrogen 2.8gm of an organic compound was digested by KJeldahl method and the evolved ammonia was absorbed in 80ml of 0.2M Sulphuric acid. The un reacted acid required 40ml of 0.4M sodium hydroxide for complete neutralisation.the percentage of the nitrogen in the compound is

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a

8%

b

80%

c

16%

d

1.6%

answer is A.

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Detailed Solution

no.of milligram equivalent react with
$N H_{3} = (N_{a} V_{a} - N_{b} V_{b})$
$\begin{matrix} N_{H_{2} S O_{4}} & V_{H_{2} S O_{4}} & N_{N a O H} & V_{N a O H} \end{matrix}$
$= [0.2 \times 2 \times 80] - (0.4 \times 40)$
$= 0.4 \times 80 - 16$
$\begin{array}{l} = 32 - 16 \\ = 16 \end{array}$
$∴ % N = \frac{1.4 \times N_{H_{2} S O_{4}} V_{H_{2} S O_{4}} (m l)}{w t o f o . c}$
$\begin{array}{l} = \frac{1.4 \times 168}{2.8} \\ % N = 8 % \end{array}$

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