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Q.

For the first order decomposition reaction :

2N2O5(g)4NO2(g)+O2(g)

Initially the total pressure is found to be 650 torr and after a very long time total pressure is found to be 1550 torr. If after 4 minutes from the start of the reaction partial pressure of O2 = 100 torr, calculate half life of the decomposition in minutes. [Given: in 3 :: 1.1 and ln 2 = 0.7) [Assume initially O2 is absent]

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answer is 7.

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Detailed Solution

2N2O5P0P0-x04NO2-2x2P0+O2-x2P02

2P0+P02+Pinert =1550

P0+Pinert =650 P0=600,Pinert =50

Now, x2=100x=200

ln2t1/2×4=ln600400t1/2=7min

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