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Q.

For the following combination of gates select the correct statement :

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a

The output is 0 when the two inputs are different

b

The output is 1 when the two inputs are different

c

The output is 1 when both the inputs are 1

d

The output is 1 when both the inputs are 0

answer is D.

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Detailed Solution

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$\begin{array}{l} y = (\bar{A} + AB) \cdot (\bar{B} + AB) \\ y = \bar{\bar{A} + AB} + \bar{\bar{B} + AB} \\ = A \cdot \bar{AB} + B \cdot \bar{AB} \\ (A + B) \bar{AB} \\ = (A + B) (\bar{A} + \bar{B}) \\ = A \bar{A} + A \bar{B} + B \bar{A} + B \bar{B} \\ = A \bar{B} + B \bar{A} \\ X - OR gate \end{array}$

OR

Truth table

Input 1	Input 2	Output
0	0	0
0	1	1
1	0	1
1	1	0

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