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For the following molecule :
Consider the following statement, if $π$ electron cloud of $C_{1} - C_{2}$ is present in the plane of paper.
(P) Fluorine is perpendicular to the plane of paper
(Q) Chlorine is present in the plane of paper
(R) Nodal plane of $π$ -electron cloud of $C_{2} - C_{3}$ is in plane of paper
(S) Nodal plane of $π$ -electron cloud of $C_{3} - C_{4}$ and $C_{1} - C_{2}$ are in the plane of chlorine atom

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$T T T T$

$FFT T$

$FT T T$

$FFTF$

answer is B.

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Detailed Solution

Chlorine and fluorine is present in the same plane.

Nodal plane of $π$ -electron cloud of $C_{2} - C_{3}$ is in plane of paper which will make the Nodal plane of $π$ -electron cloud of $C_{3} - C_{4}$ and $C_{1} - C_{2}$ are in the plane of chlorine atom.

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