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For the following reaction,
${CaCO}_{3} (s) ⟶ CaO (s) + {CO}_{2} (g)$
If at 0 K, $∆ S$ of this reaction is x cal mol^-1, then entropy of CO₂(g) at 0 K is

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-x cal

-2x cal

+x cal

0 cal

answer is C.

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Detailed Solution

$∆ S = \sum_{S_{products}} - \sum_{S_{Reactants}}$

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