For the following reaction, the mass of water produced from 445g of C₅₇H₁₁₀O₆ is :
2C₅₇H₁₁₀O_6(s) + 163O_2(g) → 114CO_2(g) + 110 H₂O_(l)

$$\begin{gathered} 2{\mathrm{C}}_{57}{\mathrm{H}}_{110}{\mathrm{O}}_6\left(\mathrm{s}\right) + 163 {\mathrm{O}}_2\left(\mathrm{g}\right) \to 114 {\mathrm{CO}}_2\left(\mathrm{g}\right) + 110 {\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right) \\ 2\times 890\mathrm{g} 110\times 18\mathrm{g} \\ 445\mathrm{g} ? \\ \mathrm{Mass} \mathrm{of} \mathrm{water} \mathrm{produced}=\frac{445}{2\times 890}\times 110\times 18=495\mathrm{g} \end{gathered}$$