For the following reaction ${\mathrm{NH}}_4{\mathrm{HS}}_{\left(\mathrm{s}\right)}\rightleftharpoons {\mathrm{NH}}_{3\left(\mathrm{g}\right)}+{\mathrm{H}}_2{\mathrm{S}}_{\left(\mathrm{g}\right)}$, the total pressure at equilibrium is 30 atm. The value of K_p is

.NH₄​SH(s) ⇄ NH₃(g) ​+ H₂​S(g)​

Partial pressure at equilibrium

P+P=30            K_P​ = $P_{N{H}_3}x P_{H_{2}S}$  = 15 x15 = 225 atm