For the following reaction ${NH}_{4} {HS}_{(s)} ⇌ {NH}_{3 (g)} + H_{2} S_{(g)}$ , the total pressure at equilibrium is 30 atm. The value of K_p is

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15 atm²

225 atm²

30 atm²

15 atm

answer is B.

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Detailed Solution

.NH₄SH(s) ⇄ NH₃(g) + H₂S(g)

Partial pressure at equilibrium

P+P=30 K_P = $P_{N H_{3}} x P_{H_{2} S}$ = 15 x15 = 225 atm

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