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For the four circles M,N,O and P, following four equations are given;
Circle: $M : x^{2} + y^{2} = 1$
Circle: $N : x^{2} + y^{2} - 2 x = 0$
Circle: $O : x^{2} + y^{2} - 2 x - 2 y + 1 = 0$
Circle : $P : x^{2} + y^{2} - 2 y = 0$
If the centre of circle M is joined with centre of the circle N, further centre of circle N is joined with centre of the circle O, centre of circle O is joined with the centre of circle P and lastly, centre of circle P is joined with centre of circle M, then these lines form the sides of a:

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Rhombus

Rectangle

Parallelogram

Square

answer is B.

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Detailed Solution

$M : x^{2} + y^{2} = 1 (0, 0) N : x^{2} + y^{2} - 2 x = 0 (1, 0) O : x^{2} + y^{2} - 2 x - 2 y + 1 = 0 (1, 1) P : x^{2} + y^{2} - 2 y = 0 (0, 1)$
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