For the four gases A, B, E, and D the value of the excluded volume per mole is same. If the order of the critical temperature is $T_{B} > T_{D} > T_{A} > T_{E}$ then the order of their liquefaction pressure at a temperature $T (T < T_{E})$ will be:

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$P_{B} < P_{D} < P_{A} < P_{E}$

$P_{D} < P_{E} < P_{A} < P_{B}$

$P_{E} < P_{A} < P_{D} < P_{B}$

$P_{A} < P_{B} < P_{E} < P_{D}$

answer is B.

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Detailed Solution

'b' is same of A, B, E, D.

$T_{C} = \frac{8 a}{27 R b}$

$\Rightarrow^{'} a'$ order $: B > D > A > E;$

$P_{C} = \frac{a}{27 b^{2}}$

$P_{C}$ order = $B > D > A > E$

Liquefaction Pressure = $= B < D < A < E$ .

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