For the gaseous reaction : $A (g) ⟶$ Products, the rate may be expressed as
Method I : $- \frac{1}{V} \cdot \frac{d n_{A}}{d t} = k_{1} \cdot C_{A}^{n}$
Method II : $- \frac{d P_{A}}{d t} = k_{2} \cdot P_{A}^{n}$
where $C_{A} = \frac{n_{A}}{V} =$ molar concentration of A and $p_{A}$ is the partial pressure of A at time 't' and 'n' is the order of reaction. The reaction is occurring at constant temperature, T = 300 K. Assume ideal behaviour of gas. Select the correct statement(s).

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$k_{1} = k_{2}$ · (RT), when n = 0

$k_{1} = k_{2}$ for any value of 'n'

$k_{1} = k_{2}$ , when n =1

$k_{1} = k_{2}$ · (RT), when n = 2

answer is B, D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$\begin{array}{l} C_{A} = \frac{P_{A}}{R T}; - \frac{d C_{A}}{d t} = \frac{- 1}{R T} \frac{d P_{A}}{d t} = k_{1} C_{A}^{n} \\ \Rightarrow - \frac{d P_{A}}{d t} = k R T \frac{{(P_{A})}^{n}}{(R T)^{n}} = k_{2} {(P_{A})}^{n} \\ ∵ n = 1; k_{1} = k_{2} \\ ∴ n = 2; \frac{k_{1}}{R T} = k_{2} \end{array}$