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Q.

For the given circuit potentiometer wire is of length 5m and resistance is 5Ω. Resistance of 4Ω is connected across the potentiometer wire with a cell of emf 10V and internal resistance 1Ω. If the balance length is found at 300cm, then emf E of each cell is

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a

3.0V

b

1.5V

c

0.67V

d

3.33V

answer is B.

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Detailed Solution

Question Image

E=Ep⋅RR+R3+rlL

E=10×55+4+1300500

E=10×510×35

E=3V

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