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For the given circuit, terminal potential differences of cells are around

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15V, 10V

12V, 15V

6V, 12V

17V, 13V

answer is D.

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Detailed Solution

$i = \frac{E_{1} - E_{2}}{r_{1} + r_{2} + R} = \frac{1}{1.6} A;$

$V_{2} = E_{2} - {ir}_{2} = 17 V$

$V_{1} = E_{1} + {ir}_{1} = 13 V$

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