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Q.

For the given circuit, the power across zener diode is _____ mw

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answer is 120.

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Detailed Solution

$I = I_{L} + I_{z}$

$I_{z} = I - I_{L}$

$I = \frac{V - V_{z}}{R_{s}} = \frac{14}{1 \times 10^{3}} = 14 mA$

$I_{L} = \frac{10}{5 \times 10^{3}} = 2 mA$

$I_{z} = 14 - 2 = 12 mA$

Power $P = I_{z} V_{z}$

$= 12 mA \times 10 V$

$= 120 mW$

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