For the given reactions :

(a) ${\mathrm{C}}_x{\mathrm{H}}_y+\left(x+\frac{y}{4}\right){\mathrm{O}}_2\to x{\mathrm{CO}}_2+\frac{y}{2}\left[{\mathrm{H}}_2\mathrm{O}\right]$

(b) ${\mathrm{N}}_2+3{\mathrm{H}}_2\underset{200\mathrm{atm}{500}^{\circ }\mathrm{C}}{⟶}[\mathrm{S}{]}_{\text{gas }}$

(c) ${\mathrm{P}}_4+\mathrm{NaOH}+{\mathrm{H}}_2\mathrm{O}\stackrel{\text{ boil }}{⟶}[\mathrm{T}{]}_{\text{gas }}$

The % ratio of valence electron of central atom vs total valence shell electrons is 62.5% in [S] and 27.77% in [T] and central atom of [S] and [T] belongs to same group then what is the correct order of increasing bond angle of[R] = 1, [S] = 2 and [T] = 3?

(If your answer is 1 < 2 < 3 then write 0123.)