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Q.

For the given thermochemical reaction H_2(g)+Br_2(l) $\to$ 2HBr_(g); heat of reaction is equal to

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a

$∆_{f} H_{HBr}^{0}$

b

$2 ∆_{f} H_{HBr}^{0}$

c

Zero

d

$\frac{∆_{f} H_{HBr}^{0}}{2}$

answer is B.

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Detailed Solution

$∆_{r} H = 2 ∆_{f} H_{HBr}^{0}$ since 2 moles of gaseous HBr is formed

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