For the homogenous reactions xA+yB→lY+mZΔH=−30kJmolm−1,ΔS=−100JK−1mol−1At what temperature the reaction is at equilibrium ?

ΔG=ΔH−TΔSAt equilibrium, ΔG=0∴ΔH−TΔS=0T=ΔHΔS=−30×1000−100=300K, i.e. ,27∘C

For the homogenous reactions xA+yB→lY+mZΔH=−30kJmolm−1,ΔS=−100JK−1mol−1At what temperature the reaction is at equilibrium ?

ΔG=ΔH−TΔSAt equilibrium, ΔG=0∴ΔH−TΔS=0T=ΔHΔS=−30×1000−100=300K, i.e. ,27∘C

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For the homogenous reactions
$\begin{array}{l} xA + yB \to lY + mZ \\ ΔH = - 30 {kJmolm}^{- 1}, ΔS = - 100 {JK}^{- 1} {mol}^{- 1} \end{array}$
At what temperature the reaction is at equilibrium ?

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50°C

27°C

250°C

300°C

answer is D.

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Detailed Solution

$ΔG = ΔH - TΔS$
At equilibrium, $ΔG = 0$
$\begin{array}{l} ∴ ΔH - TΔS = 0 \\ T = \frac{ΔH}{ΔS} = \frac{- 30 \times 1000}{- 100} = 300 K, i.e., 27^{\circ} C \end{array}$

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For the homogenous reactions xA+yB→lY+mZΔH=−30kJmolm−1,ΔS=−100JK−1mol−1At what temperature the reaction is at equilibrium ?

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For the homogenous reactions
$\begin{array}{l} xA + yB \to lY + mZ \\ ΔH = - 30 {kJmolm}^{- 1}, ΔS = - 100 {JK}^{- 1} {mol}^{- 1} \end{array}$
At what temperature the reaction is at equilibrium ?