For the hyperbola $\frac{x^2}{9}-\frac{y^2}{3}=1$ the incorrect statements are

$\frac{x^2}{9}-\frac{y^2}{3}=1;9(e^2-1)$ 
$\Rightarrow e=\frac{2}{\sqrt{3}}$ equation of pair of asymptotes is $\frac{x^2}{9}=\frac{y^2}{3}\Rightarrow y=\pm \frac{x}{\sqrt{3}}$
$\Rightarrow$ Angle between asymptotes = $\frac{\pi }{3}$
Length of L.R. $=\frac{2b^2}{a}=2$
Product of perpendicular distance of any point
$P(3\sec \theta ,\sqrt{3}\tan \theta )$ from asymptotes
$P_1{P}_2=\frac{|3\sec \theta -3\tan \theta |}{2}\frac{|3\sec \theta -3\tan \theta |}{2}$ 
$=\frac{9}{4}>2$