For the line $\frac{x-1}{1}=\frac{y-2}{2}=\frac{z-3}{3}$ which one of the following is incorrect?

The line is passing through $A(1,2,3)$ and it is having d.r.s 1, 2, 3

$x-2y+z=0$ is passes through A and having normal d.r.s $1,-2,3$

Normal is perpendicular to the line (0,0,0) lies on given line

$\therefore \text{ Equation of the line can be written as }\frac{x}{1}=\frac{y}{2}=\frac{z}{3}$

 (2,3,5) is not satisfying equation of the line

$\therefore \left(3\right)$ is incorrect