For the parabola $y^2+8x-12y+20=0$ which of
the following in not correct 

$(y-6{)}^2=-8(x-2)\text{ or }{Y}^2=4AX$ where $Y=y-6$

$X=x-2,A=-2,$vertex is $(2,6),$ focus is $(X=A,Y=0)$

i.e., (0, 6) axis is$Y = 0$ i.e.$y = 6$.and length of the

latus rectum $=\left|4A\right|=8$.