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Q.

For the particle moving with uniform acceleration along a straight line ABC, velocity at A and B are 6m/s and 9m/s respectively. If AB : BC = 5 :16, then its velocity at C is

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a

12 m/s

b

21.5 m/s

c

9.6 m/s

d

15 m/s

answer is C.

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Detailed Solution

:Vc2−VB22(BC)=VB2−VA22(AB)= acceleration

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