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For the plane $Π \equiv 4 x - 3 y + 2 z - 3 = 0,$ the points $A (- 2, 1, 2), B = (3, 1, - 2)$

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Lie on the same side of $Π = 0$

Lie on the opposite sides of $Π = 0$

Lie on the normal to $Π = 0$

Lie on $Π = 0$

answer is B.

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Detailed Solution

${II}_{111} = - 8 - 3 + 6 - 3 = - 8; {II}_{222} = 12 - 3 - 4 - 3 = 2$

The points lie on the opposite side of II = 0

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