For the projectile shown in figure, the time of flight and range along the inclined plane is: (g=10 m/s²)

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Range of the projectile along the inclined plane is 145.71m

The time of flight of the projectile along the inclined plane is 63.1s

Range of the projectile along the inclined plane is 145.71m

The time of flight of the projectile along the inclined plane is 1.69s

Range of the projectile along the inclined plane is 145.71m

The time of flight of the projectile along the inclined plane is 6.31s

Range of the projectile along the inclined plane is 129m

The time of flight of the projectile along the inclined plane is 63.1s

answer is B.

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Detailed Solution

$t i m e o f f l i g h t = T = \frac{2 u \sin (α + β)}{g \cos β} T = \frac{(2) (20 \sqrt{2}) \sin (45^{0} + 30^{0})}{(10) \cos 30^{0}} T = \frac{(2) (20 \sqrt{2}) \sin (75^{0})}{(10) \frac{\sqrt{3}}{2}} = \frac{8 \times 1.414 \times 0.96}{\sqrt{3}} = 6.31 s r a n g e = R = \frac{u^{2}}{g \cos^{2} β} [\sin (2 α + β) + \sin β] R = \frac{{(20 \sqrt{2})}^{2} [\sin (2 \times 45^{0} + 30^{0}) + \sin 30^{0}]}{(10) \cos^{2} 30^{0}} = 145.71 m$