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For the reaction $2 A + B ⇌ 3 C$ at $295 K; K_{C} = 40$ . A “4” Lit Vessel contains 2,1 and 4 moles of A,B and C respectively. The reaction at the same temperature.

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Must proceed in forward direction

Can’t be predicted

Must be in equilibrium

Must proceed in Backward direction

answer is A.

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Detailed Solution

$K_{C} = 40 Q_{C} = \frac{{[C]}^{3}}{{[A]}^{2} [B]} = \frac{{(\frac{4}{4})}^{3}}{{(\frac{2}{4})}^{2} (\frac{1}{4})} = \frac{64}{4} = 16 Q_{C} < K_{C}, f o r w a r d d i r e c t i o n f a v o u r e d .$

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