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For the reaction:
$2 F e S_{2} + \frac{11}{2} O_{2} \to F e_{2} O_{3} + 4 S O_{2}$ what will be the equivalent weight of $F e S_{2}$ , if the
molecular weight of $F e S_{2}$ is $M$ ?

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M/8

M/11

M/4

answer is C.

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Detailed Solution

$2 F e S_{2} + \frac{11}{2} O_{2} \to F e_{2} O_{3} + 4 S O_{2}$
Two moles of $F e S_{2}$ losing 22electrons
n-factor of $F e S_{1} = 11$ .

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