For the reaction $A\rightleftharpoons B$

 

 

 

 

 

 

INCORRECT statement about this is 

In G Vs $\xi$ graph, slope is $\Delta G$

A) At X, $\Delta G$ is –ve. So reaction is spontaneous  $(Q_C<k_C)$
B) At Y, $\Delta G$  is +ve. So reaction is non-spontaneous $(Q_C>k_C)$
C) At Z, $\Delta G$ is zero but not $\Delta G^{\circ }$
D) There is no relation between $K_{eq}$ and time required to reach equilibrium state.