Q.

For the reaction A(g)B(g), the value of the equilibrium constant at 400K and 1atm is equal to 1000.0. The value of ΔrG0 for the reaction at 400K and 1atm in Jmol1 is xR, where x is _______(Rounded off to the nearest integer) (ln10=2.303) 

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answer is 2764.

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Detailed Solution

ΔG0=RTlnKp=R(400)ln(10)3=R(400×3×2.3)

ΔG0=2764R

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