For the reaction $A\left(s\right)\to A\left(g\right)$, the variation of log$K_P^0$  vs $\frac{1}{T}$ is given by :
 
If  $S_m^0,A\left(g\right)$ is  31.78 cal/K mole, then calculate  $S_m^0$ A(s) in cal/K mole.
R= 2 Cal  $mo{l}^{-1}{K}^{-1}$. ln5=2.303 log 5
Report your answer to nearest integer