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Q.

For the reaction,  A+2B⇌2C, the rate constant for the forward and the backward reactions are 1×10−4 and 2.5×10−2 respectively. The value of equilibrium constant, K, for the reaction would be :

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a

2.5×102

b

2.5×10−2

c

4×10−3

d

1×10−4

answer is C.

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Detailed Solution

The value of equilibrium constant, K, for the reaction would be:

K=KfKb

K=1×10−42.5×10−2

K=4×10−3

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