For the reaction ; CaCO3(s)⇌CaO(s)+CO2(g),Kp=1.6 atm at 800∘C If 20g of CaCO3 were kept in a 10 litre vessel at 800∘C, the amount of CaCO3 that remained at that remained at equilibrium

PCO2=1.6atmnCO2=1.6×100.0821×1073=0.182CaCO3⇌CaO+CO220100−0.1829%

For the reaction ; CaCO3(s)⇌CaO(s)+CO2(g),Kp=1.6 atm at 800∘C If 20g of CaCO3 were kept in a 10 litre vessel at 800∘C, the amount of CaCO3 that remained at that remained at equilibrium

PCO2=1.6atmnCO2=1.6×100.0821×1073=0.182CaCO3⇌CaO+CO220100−0.1829%

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For the reaction ; ${CaCO}_{3} (s) ⇌ CaO (s) + {CO}_{2} (g), K_{p} = 1.6$ atm at $800^{\circ} C$ If $20 g$ of ${CaCO}_{3}$ were kept in a 10 litre vessel at $800^{\circ} C$ , the amount of ${CaCO}_{3}$ that remained at that remained at equilibrium

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$\begin{array}{l} P_{{CO}_{2}} = 1.6 atm \\ n_{{CO}_{2}} = \frac{1.6 \times 10}{0.0821 \times 1073} = 0.182 \\ {CaCO}_{3} ⇌ CaO + {CO}_{2} \\ \frac{20}{100} - 0.182 \\ 9 % \end{array}$

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For the reaction ; CaCO3(s)⇌CaO(s)+CO2(g),Kp=1.6 atm at 800∘C If 20g of CaCO3 were kept in a 10 litre vessel at 800∘C, the amount of CaCO3 that remained at that remained at equilibrium

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For the reaction ; ${CaCO}_{3} (s) ⇌ CaO (s) + {CO}_{2} (g), K_{p} = 1.6$ atm at $800^{\circ} C$ If $20 g$ of ${CaCO}_{3}$ were kept in a 10 litre vessel at $800^{\circ} C$ , the amount of ${CaCO}_{3}$ that remained at that remained at equilibrium