For the reaction  ${\left[Cu{\left(N{H}_3\right)}_4\right]}^{2+}+H_{2}O\underset{ }{\rightleftharpoons }{\left[Cu{\left(N{H}_3\right)}_3{H}_{2}O\right]}^{2+}+N{H}_3$. The net  rate of reaction at any time is given by : rate = $2.0\times {10}^{-4}\left[{\left[Cu{\left(N{H}_3\right)}_4\right]}^{2+}\right]$  $\left[H_{2}O\right]-3.0\times {10}^5\left[{\left[Cu{\left(N{H}_3\right)}_3{H}_{2}O\right]}^{2+}\right]\left[N{H}_3\right]$

The correct statement is (are) :