For the reaction equilibrium, 2NOBr(g)⇌2NO(g)+Br2(g) if PBr2=P9 at equilibrium and P is total pressure. The ratio Kp/P is equal to:

2NOBr(g)6P9⇌2NO2P9+Br2P9Total pressure =6P9+2P9+P9=PKp=PNO2PBr2PNOBr2=(2P/9)2(P/9)6P92=P81

For the reaction equilibrium, 2NOBr(g)⇌2NO(g)+Br2(g) if PBr2=P9 at equilibrium and P is total pressure. The ratio Kp/P is equal to:

2NOBr(g)6P9⇌2NO2P9+Br2P9Total pressure =6P9+2P9+P9=PKp=PNO2PBr2PNOBr2=(2P/9)2(P/9)6P92=P81

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For the reaction equilibrium, $2 NOBr (g) ⇌ 2 NO (g) + {Br}_{2} (g)$ if $P_{{Br}_{2}} = \frac{P}{9}$ at equilibrium and P is total pressure. The ratio K_p/P is equal to:

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1 /3

1/9

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answer is B.

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Detailed Solution

$\underset{\frac{6 P}{9}}{2 NOBr (g)} ⇌ \underset{\frac{2 P}{9}}{2 NO} + \underset{\frac{P}{9}}{{Br}_{2}}$
Total pressure $= \frac{6 P}{9} + \frac{2 P}{9} + \frac{P}{9} = P$
$K_{p} = \frac{{(P_{NO})}^{2} (P_{{Br}_{2}})}{{(P_{NOBr})}^{2}} = \frac{(2 P / 9)^{2} (P / 9)}{{(\frac{6 P}{9})}^{2}} = \frac{P}{81}$