For the reaction I−+ClO3−+H2SO4→Cl−+HSO4−+I2The correct statement are

6I−+Cl+5O3-+6H2S+6O4→Cl−+3I2+3H2O+6HS+6O4−Iodine is oxidized and 'Cl' is reduced.

For the reaction I−+ClO3−+H2SO4→Cl−+HSO4−+I2The correct statement are

6I−+Cl+5O3-+6H2S+6O4→Cl−+3I2+3H2O+6HS+6O4−Iodine is oxidized and 'Cl' is reduced.

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For the reaction $I^{-} + C l O_{3}^{-} + H_{2} S O_{4} \to C l^{-} + H S O_{4}^{-} + I_{2}$
The correct statement are

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Stoichiometric coefficient of $H S O_{4}^{-}$ is 6

Iodide is oxidized

Sulphur is reduced

$H_{2} O$ is one of the products.

answer is A, B, D.

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$6 I^{-} + \overset{+ 5}{C l} O_{3}^{-} + 6 H_{2} \overset{+ 6}{S} O_{4} \to C l^{-} + 3 I_{2} + 3 H_{2} O + 6 H \overset{+ 6}{S} O_{4}^{-}$

Iodine is oxidized and 'Cl' is reduced.

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For the reaction I−+ClO3−+H2SO4→Cl−+HSO4−+I2The correct statement are

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For the reaction $I^{-} + C l O_{3}^{-} + H_{2} S O_{4} \to C l^{-} + H S O_{4}^{-} + I_{2}$
The correct statement are