For the reaction the $C_{2} H_{5} OH + {Br}^{-} ⇌ C_{2} H_{5} Br + {OH}^{-}$ , equilibrium will shift to the right on

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An Intiative by Sri Chaitanya

Exposing the system to light

Adding an alkali

Adding an acid

Adding C₂H₅Br

answer is C.

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Detailed Solution

Addition of acid causes the decrease of [OH^-] and shift to wards right side.

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